|
Hi.
I found some overhead code in /src/sys/net/if_ethersubr.c and /src/sys/netgraph/ng_ether.c It contains strings, like bcopy(src, dst, ETHER_ADDR_LEN); When src and dst are "struct ether_addr*", and ETHER_ADDR_LEN equal 6. This code call every time, when we send Ethernet packet. On example, on my machine in invoked nearly 20K per second. Why we are use bcopy(), to copy only 6 bytes? Answer - in some architectures we are can not directly copy unaligned data. I propose this solution. In file /usr/src/include/net/ethernet.h add this lines: static inline void ether_addr_copy(ether_addr* src, ether_addr* dst) { #if defined(__i386__) || defined(__amd64__) *dst = *src; #else bcopy(src, dst, ETHER_ADDR_LEN); #endif } On platform i386 gcc produce like this code: leal -30(%ebp), %eax leal 6(%eax), %ecx leal -44(%ebp), %edx movl (%edx), %eax movl %eax, (%ecx) movzwl 4(%edx), %eax movw %ax, 4(%ecx) And clang produce this: movl -48(%ebp), %ecx movl %ecx, -26(%ebp) movw -44(%ebp), %si movw %si, -22(%ebp) All this variants are much faster, than bcopy() _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
On Aug 20, 2012, at 8:46 AM, Mitya wrote: > Hi. > I found some overhead code in /src/sys/net/if_ethersubr.c and /src/sys/netgraph/ng_ether.c > > It contains strings, like bcopy(src, dst, ETHER_ADDR_LEN); > When src and dst are "struct ether_addr*", and ETHER_ADDR_LEN equal 6. > This code call every time, when we send Ethernet packet. > On example, on my machine in invoked nearly 20K per second. > > Why we are use bcopy(), to copy only 6 bytes? > Answer - in some architectures we are can not directly copy unaligned data. True for shorts, longs, etc. But why do we need it for ether_addr? It is a struct that's just an array... That's always safe. > I propose this solution. > > In file /usr/src/include/net/ethernet.h add this lines: > > static inline void ether_addr_copy(ether_addr* src, ether_addr* dst) { > #if defined(__i386__) || defined(__amd64__) Bleck. that's uber ugly. We have a define for unaligned vs aligned architectures. we should use that here. If we even need this ifdef at all. Warner > *dst = *src; > #else > bcopy(src, dst, ETHER_ADDR_LEN); > #endif > } > > On platform i386 gcc produce like this code: > leal -30(%ebp), %eax > leal 6(%eax), %ecx > leal -44(%ebp), %edx > movl (%edx), %eax > movl %eax, (%ecx) > movzwl 4(%edx), %eax > movw %ax, 4(%ecx) > And clang produce this: > movl -48(%ebp), %ecx > movl %ecx, -26(%ebp) > movw -44(%ebp), %si > movw %si, -22(%ebp) > > > All this variants are much faster, than bcopy() > > _______________________________________________ > [hidden email] mailing list > http://lists.freebsd.org/mailman/listinfo/freebsd-hackers > To unsubscribe, send any mail to "[hidden email]" _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Dmitry S. Luhtionov
> #if defined(__i386__) || defined(__amd64__)
> *dst = *src; > #else > bcopy(src, dst, ETHER_ADDR_LEN); #else short *tmp1=((*short)src),*tmp2=((*short)dst); *tmp2=*tmp1; *(tmp2+1)=*(tmp1+1); *(tmp2+2)=*(tmp1+2); or use ++. i think it is always aligned to 2 bytes and this should produce usable code on any CPU? should be 6 instructions on MIPS and PPC IMHO. _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
On Aug 20, 2012, at 10:48 AM, Wojciech Puchar wrote: >> #if defined(__i386__) || defined(__amd64__) >> *dst = *src; >> #else >> bcopy(src, dst, ETHER_ADDR_LEN); > #else > short *tmp1=((*short)src),*tmp2=((*short)dst); > *tmp2=*tmp1; *(tmp2+1)=*(tmp1+1); *(tmp2+2)=*(tmp1+2); > > or use ++. > > i think it is always aligned to 2 bytes and this should produce usable code on any CPU? should be 6 instructions on MIPS and PPC IMHO. We should tag it as __aligned(2) then, no? If so, then the compiler should generate the code you posted. Warner _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
>> or use ++.
>> >> i think it is always aligned to 2 bytes and this should produce usable code on any CPU? should be 6 instructions on MIPS and PPC IMHO. > > We should tag it as __aligned(2) then, no? If so, then the compiler should generate the code you posted. should is the most important word in Your post. what it actually do - i don't know. _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
On Aug 20, 2012, at 1:17 PM, Wojciech Puchar wrote: >>> or use ++. >>> >>> i think it is always aligned to 2 bytes and this should produce usable code on any CPU? should be 6 instructions on MIPS and PPC IMHO. >> >> We should tag it as __aligned(2) then, no? If so, then the compiler should generate the code you posted. > should is the most important word in Your post. what it actually do - i don't know. If we are requiring this to be __aligned(2), we should tag it as such to enforce this. Even without this tagging, the code to do a structure level copy of 6 bytes is going to be tiny... Warner _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Warner Losh
On Mon, 20 Aug 2012 13:05:51 MDT Warner Losh <[hidden email]> wrote:
> > On Aug 20, 2012, at 10:48 AM, Wojciech Puchar wrote: > > >> #if defined(__i386__) || defined(__amd64__) > >> *dst =3D *src; > >> #else > >> bcopy(src, dst, ETHER_ADDR_LEN); > > #else > > short *tmp1=3D((*short)src),*tmp2=3D((*short)dst); > > *tmp2=3D*tmp1; *(tmp2+1)=3D*(tmp1+1); *(tmp2+2)=3D*(tmp1+2); > > > > or use ++. > > > > i think it is always aligned to 2 bytes and this should produce usable > code on any CPU? should be 6 instructions on MIPS and PPC IMHO. > > We should tag it as __aligned(2) then, no? If so, then the compiler > should generate the code you posted. Doesn't gcc inline memcpy these days? _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Warner Losh
20.08.2012 22:20, Warner Losh написал:
> On Aug 20, 2012, at 1:17 PM, Wojciech Puchar wrote: > >>>> or use ++. >>>> >>>> i think it is always aligned to 2 bytes and this should produce usable code on any CPU? should be 6 instructions on MIPS and PPC IMHO. >>> We should tag it as __aligned(2) then, no? If so, then the compiler should generate the code you posted. >> should is the most important word in Your post. what it actually do - i don't know. > If we are requiring this to be __aligned(2), we should tag it as such to enforce this. > > Even without this tagging, the code to do a structure level copy of 6 bytes is going to be tiny... > > Warner > *(u_int32_t *)(dst) = *(u_int32_t *)(src); *(u_int16_t *)&(dst->octet[4]) = *(u_int16_t *)&(src->octet[4]); But, internal gcc and clang optimisations are much better, than my attempt. For aligned platforms (2 bytes aligned) best choice is *dst = *src; _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Warner Losh
>
> Even without this tagging, the code to do a structure level copy of 6 bytes is going to be tiny... true. just to make sure it will be absolutely portable how about bcopymacaddress(dst,src) and then define it whatever you find it fastest on any architecture? _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Dmitry S. Luhtionov
On Mon, Aug 20, 2012 at 05:46:12PM +0300, Mitya wrote:
> Hi. > I found some overhead code in /src/sys/net/if_ethersubr.c and > /src/sys/netgraph/ng_ether.c > > It contains strings, like bcopy(src, dst, ETHER_ADDR_LEN); > When src and dst are "struct ether_addr*", and ETHER_ADDR_LEN equal 6. > This code call every time, when we send Ethernet packet. > On example, on my machine in invoked nearly 20K per second. > > Why we are use bcopy(), to copy only 6 bytes? > Answer - in some architectures we are can not directly copy unaligned data. > > I propose this solution. > > In file /usr/src/include/net/ethernet.h add this lines: > > static inline void ether_addr_copy(ether_addr* src, ether_addr* dst) { > #if defined(__i386__) || defined(__amd64__) > *dst = *src; > #else > bcopy(src, dst, ETHER_ADDR_LEN); > #endif > } > > On platform i386 gcc produce like this code: > leal -30(%ebp), %eax > leal 6(%eax), %ecx > leal -44(%ebp), %edx > movl (%edx), %eax > movl %eax, (%ecx) > movzwl 4(%edx), %eax > movw %ax, 4(%ecx) > And clang produce this: > movl -48(%ebp), %ecx > movl %ecx, -26(%ebp) > movw -44(%ebp), %si > movw %si, -22(%ebp) > > > All this variants are much faster, than bcopy() > A bit orthogonal to this but also related to the performance impact of these bcopy() calls, for !__NO_STRICT_ALIGNMENT architectures these places probably should use memcpy() instead as bcopy() additionally has to check for overlap while the former does not. Overlaps unlikely are an issue in these cases and at least NetBSD apparently has done the switch to memcpy() 5.5 years ago. Marius _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
On Tue, Aug 21, 2012 at 12:26:30PM +0200, Marius Strobl wrote:
... > > Why we are use bcopy(), to copy only 6 bytes? > > Answer - in some architectures we are can not directly copy unaligned data. > > > > I propose this solution. > > > > In file /usr/src/include/net/ethernet.h add this lines: > > > > static inline void ether_addr_copy(ether_addr* src, ether_addr* dst) { > > #if defined(__i386__) || defined(__amd64__) > > *dst = *src; > > #else > > bcopy(src, dst, ETHER_ADDR_LEN); > > #endif > > } > > All this variants are much faster, than bcopy() > > > > A bit orthogonal to this but also related to the performance > impact of these bcopy() calls, for !__NO_STRICT_ALIGNMENT > architectures these places probably should use memcpy() > instead as bcopy() additionally has to check for overlap > while the former does not. Overlaps unlikely are an issue > in these cases and at least NetBSD apparently has done the > switch to memcpy() 5.5 years ago. even more orthogonal: I found that copying 8n + (5, 6 or 7) bytes was much much slower than copying a multiple of 8 bytes. For n=0, 1,2,4,8 bytes are efficient, other cases are slow (turned into 2 or 3 different writes). The netmap code uses a pkt_copy routine that does exactly this rounding, gaining some 10-20ns per packet for small sizes. cheers luigi _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Warner Losh
On Mon, Aug 20, 2012 at 01:20:29PM -0600, Warner Losh wrote:
> > On Aug 20, 2012, at 1:17 PM, Wojciech Puchar wrote: > > >>> or use ++. > >>> > >>> i think it is always aligned to 2 bytes and this should produce usable code on any CPU? should be 6 instructions on MIPS and PPC IMHO. > >> > >> We should tag it as __aligned(2) then, no? If so, then the compiler should generate the code you posted. > > should is the most important word in Your post. what it actually do - i don't know. > > If we are requiring this to be __aligned(2), we should tag it as such to enforce this. > > Even without this tagging, the code to do a structure level copy of 6 bytes is going to be tiny... > While the __aligned(2) approach certainly works, I've actually rather mixed experiences on x86 with it as the compiler doesn't necessarily produce the small and efficient one would expect from code it. Such a change certainly shouldn't be done just on the assumption that the compiler has all hints required to produce good code from it but the resulting asm should be verified across all affected architectures. Marius _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
21.08.2012 14:26, Marius Strobl написал:
> On Mon, Aug 20, 2012 at 01:20:29PM -0600, Warner Losh wrote: >> On Aug 20, 2012, at 1:17 PM, Wojciech Puchar wrote: >> >>>>> or use ++. >>>>> >>>>> i think it is always aligned to 2 bytes and this should produce usable code on any CPU? should be 6 instructions on MIPS and PPC IMHO. >>>> We should tag it as __aligned(2) then, no? If so, then the compiler should generate the code you posted. >>> should is the most important word in Your post. what it actually do - i don't know. >> If we are requiring this to be __aligned(2), we should tag it as such to enforce this. >> >> Even without this tagging, the code to do a structure level copy of 6 bytes is going to be tiny... >> > While the __aligned(2) approach certainly works, I've actually rather > mixed experiences on x86 with it as the compiler doesn't necessarily > produce the small and efficient one would expect from code it. Such > a change certainly shouldn't be done just on the assumption that the > compiler has all hints required to produce good code from it but the > resulting asm should be verified across all affected architectures. > > Marius > only i386 and amd64 architectures. _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Dmitry S. Luhtionov
On Monday, August 20, 2012 10:46:12 am Mitya wrote:
> Hi. > I found some overhead code in /src/sys/net/if_ethersubr.c and > /src/sys/netgraph/ng_ether.c > > It contains strings, like bcopy(src, dst, ETHER_ADDR_LEN); > When src and dst are "struct ether_addr*", and ETHER_ADDR_LEN equal 6. > This code call every time, when we send Ethernet packet. > On example, on my machine in invoked nearly 20K per second. > > Why we are use bcopy(), to copy only 6 bytes? > Answer - in some architectures we are can not directly copy unaligned data. > > I propose this solution. > > In file /usr/src/include/net/ethernet.h add this lines: > > static inline void ether_addr_copy(ether_addr* src, ether_addr* dst) { > #if defined(__i386__) || defined(__amd64__) > *dst = *src; > #else > bcopy(src, dst, ETHER_ADDR_LEN); > #endif > } Doesn't '*dst = *src' just work on all platforms? -- John Baldwin _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Marius Strobl
On Aug 21, 2012, at 5:26 AM, Marius Strobl wrote: > On Mon, Aug 20, 2012 at 01:20:29PM -0600, Warner Losh wrote: >> >> On Aug 20, 2012, at 1:17 PM, Wojciech Puchar wrote: >> >>>>> or use ++. >>>>> >>>>> i think it is always aligned to 2 bytes and this should produce usable code on any CPU? should be 6 instructions on MIPS and PPC IMHO. >>>> >>>> We should tag it as __aligned(2) then, no? If so, then the compiler should generate the code you posted. >>> should is the most important word in Your post. what it actually do - i don't know. >> >> If we are requiring this to be __aligned(2), we should tag it as such to enforce this. >> >> Even without this tagging, the code to do a structure level copy of 6 bytes is going to be tiny... >> > > While the __aligned(2) approach certainly works, I've actually rather > mixed experiences on x86 with it as the compiler doesn't necessarily > produce the small and efficient one would expect from code it. Such > a change certainly shouldn't be done just on the assumption that the > compiler has all hints required to produce good code from it but the > resulting asm should be verified across all affected architectures. Very true... I would have thought that went without saying... Warner_______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Wojciech Puchar-5
On Aug 21, 2012, at 1:42 AM, Wojciech Puchar wrote: >> >> Even without this tagging, the code to do a structure level copy of 6 bytes is going to be tiny... > > true. > > just to make sure it will be absolutely portable how about > > bcopymacaddress(dst,src) > > and then define it whatever you find it fastest on any architecture? How about just changing it to the *dst = *src, compiling it on all architectures and then deciding if the improvement of the code from a hand-tweaked thing is worth that uglification? Warner _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
Hi,
What about just creating an ETHER_ADDR_COPY(dst, src) and putting that in a relevant include file, then hide the ugliness there? The same benefits will likely appear when copying wifi MAC addresses to/from headers. Thanks, I'm glad someone noticed this. Adrian _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Marius Strobl
> On Mon, Aug 20, 2012 at 05:46:12PM +0300, Mitya wrote:
> > Hi. > > I found some overhead code in /src/sys/net/if_ethersubr.c and > > /src/sys/netgraph/ng_ether.c > > > > It contains strings, like bcopy(src, dst, ETHER_ADDR_LEN); > > When src and dst are "struct ether_addr*", and ETHER_ADDR_LEN equal 6. Only ng_ether.c contains such strings. if_ethersubr.c doesn't exist. if_ether.c exists, but was converted to use memcpy() 17.25 years ago. > > This code call every time, when we send Ethernet packet. > > On example, on my machine in invoked nearly 20K per second. > > > > Why we are use bcopy(), to copy only 6 bytes? > > Answer - in some architectures we are can not directly copy unaligned data. > > > > I propose this solution. > > > > In file /usr/src/include/net/ethernet.h add this lines: > > > > static inline void ether_addr_copy(ether_addr* src, ether_addr* dst) { > > #if defined(__i386__) || defined(__amd64__) > > *dst = *src; > > #else > > bcopy(src, dst, ETHER_ADDR_LEN); > > #endif > > } > > > > On platform i386 gcc produce like this code: > > leal -30(%ebp), %eax > > leal 6(%eax), %ecx > > leal -44(%ebp), %edx > > movl (%edx), %eax > > movl %eax, (%ecx) > > movzwl 4(%edx), %eax > > movw %ax, 4(%ecx) > > And clang produce this: > > movl -48(%ebp), %ecx > > movl %ecx, -26(%ebp) > > movw -44(%ebp), %si > > movw %si, -22(%ebp) > > > > All this variants are much faster, than bcopy() You mean "as much as 5 nanoseconds faster". Possibly even 10 nanoseconds faster. > A bit orthogonal to this but also related to the performance > impact of these bcopy() calls, for !__NO_STRICT_ALIGNMENT > architectures these places probably should use memcpy() > instead as bcopy() additionally has to check for overlap > while the former does not. Overlaps unlikely are an issue > in these cases and at least NetBSD apparently has done the > switch to memcpy() 5.5 years ago. This is essentially just a style bug. FreeBSD switched to memcpy() 17.25 years ago for selected networking copying. memcpy() is supposed to be used if and only if compilers can optimize it. This means that the size must be fixed and small, and of course that the copies don't overlap. Otherwise, compilers can't do any better than call an extern copying routine, which is memcpy() in practice. memcpy() was interntionally left out in FreeBSD until it was added 17.25 years ago to satisfy the changes to use memcpy() in networking code (since with -O0, memcpy() won't be inlined and the extern memcpy() gets used). Other uses are style bugs, but there are many now :-(. bcopy() is still the primary interface, and might be faster than memcpy(), especially for misaligned cases, but in practice it isn't, except in the kernel on Pentium1 in 1996-1998 where I only optimized (large) bcopy()s. Since it has to support overlapping copies it is inherently slower. Although compilers can't do better for large copying than call an extern routine, some compilers bogusly inline it to something like "rep movsd" on i386, (or worse, to a very large number of loads and stores). gcc used to have a very large threshold for inlining moderately-sized copies and/or for switching between "rep movsd" and load/store. It now understands better than ut doesn't understand memory, and has more reasonable thresholds. Or rather the thresholds are more MD. gcc still makes a mess with some CFLAGS: % struct foo % { % short x; % struct bar { % short yy[31]; % } y; % } s, t; % % foo() % { % s.y = t.y; % } With just -O, gcc-4.2.1 -O on i386 handles this very badly, by generating 15 misaligned 32-bit load/stores followed by 1 aligned 16-bit load/store. With -march=<almost anything>, it generates 1 16-bit aligned load-store followed by an aligned "rep movsd" with a count of 15. The latter is not too bad. Similarly for yy[32]. But for yy[33] it switches to a call to memcpy() even with plain -O. However, improvements in memory systems and branch prediction since Pentium1 in 1996-98 mean that optimimizing copying mostly gets nowhere. Copying is either from the cache[s], in which case it is fast (~1 nanosecond per 128 bits for L1), or it is not from the caches in which case it is slow (~50-200 nanseconds per cache miss). With 6-byte ethernet addresses, using bcopy() does slow the copying to considerably below 1 nanosecond per 128 bits (a sloppy estimate gives 5-10 ns/call), but it's hard for a single call to be made often enough to make a significant difference. Someone mentioned 20000 calls. That's the same as 0 calls: 20000 * 10 nsec = 200 usec = 0.05% of 1 CPU. If anyone cared about this, then they would use __builtin_memcpy() instead of memcpy(). (Note that the point of the 17.25-year old optimization has been defeated for ~10 years by turning off _all_ builtins, which was initially done mainly to kill builtin putc(). (-ffreestanding should have done that.) So gcc inlines struct copying for small structs, but never inlines memcpy(), or strlen(), or other unimportant things.) I once used the following to partially fix this, but stopped using it because it made no observable difference: % diff -c2 ./sys/systm.h~ ./sys/systm.h % *** ./sys/systm.h~ Sat Oct 13 12:43:54 2007 % --- ./sys/systm.h Sat Oct 13 12:43:56 2007 % *************** % *** 188,193 **** % --- 188,204 ---- % void bcopy(const void *from, void *to, size_t len) __nonnull(1) __nonnull(2); % void bzero(void *buf, size_t len) __nonnull(1); % + #if 1 % + #define bzero(p, n) ({ \ % + if (__builtin_constant_p(n) && (n) <= 64) \ % + __builtin_memset((p), 0, (n)); \ % + else \ % + (bzero)((p), (n)); \ % + }) % + #endif % % void *memcpy(void *to, const void *from, size_t len) __nonnull(1) __nonnull(2); % + #if 1 % + #define memcpy(to, from, n) __builtin_memcpy((to), (from), (n)) % + #endif % % int copystr(const void * __restrict kfaddr, void * __restrict kdaddr, In another set of dead patches, I changed lots of memcpy()s in networking code to __builtin_memcpy()'s. There is another set of style bugs and micro-pessimizations involving other mem* functions starting with bzero(). The above avoids the micro-pessimizations for the usual case of memset() to 0, at a cost of rewarding the style bug. Summary: use builtin memcpy() for small copies, and don't try hard to otherwise optimize this. Bruce _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by Luigi Rizzo-5
luigi wrote:
> even more orthogonal: > > I found that copying 8n + (5, 6 or 7) bytes was much much slower than > copying a multiple of 8 bytes. For n=0, 1,2,4,8 bytes are efficient, > other cases are slow (turned into 2 or 3 different writes). > > The netmap code uses a pkt_copy routine that does exactly this > rounding, gaining some 10-20ns per packet for small sizes. I don't believe 10-20ns for just the extra bytes. memcpy() ends up with a movsb to copy the extra bytes. This can be slow, but I don't believe 10-20ns (except on machines running at i486 speeds of course). % ENTRY(memcpy) % pushl %edi % pushl %esi % movl 12(%esp),%edi % movl 16(%esp),%esi % movl 20(%esp),%ecx % movl %edi,%eax % shrl $2,%ecx /* copy by 32-bit words */ % cld /* nope, copy forwards */ % rep % movsl % movl 20(%esp),%ecx % andl $3,%ecx /* any bytes left? */ This avoids a branch. Some optimization manuals say that the branch is actually better for some machines, The above 2 instructions have a throughput of 1 per cycle each on modern x86. Latency might be 6 cycles. % rep Maybe 5-15 cycles throughput. % movsb Now hopefully at most 1 cycle/byte. Some hardware might combine the bytes as much as possible, so the whole function should use 1 single "rep movsb" and let the hardware do it all. % popl %esi % popl %edi % ret Well, it's easy to get a latency of 20 cycles 5-10 ns) and maybe even a throughput of that. But all of thus is out of order on modern x86. The extra cycles for the movsb might not cost at all if nothing accesses the part of the target that they were written to soon. With builtin memcpy, 6 bytes would be done using load/store of 4+2 bytes and thus take the same time as 8 bytes on i386, but on amd64 8 bytes would be faster. Bruce _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
|
In reply to this post by John Baldwin
jhb wrote:
> On Monday, August 20, 2012 10:46:12 am Mitya wrote: > > ... > > I propose this solution. > > > > In file /usr/src/include/net/ethernet.h add this lines: > > > > static inline void ether_addr_copy(ether_addr* src, ether_addr* dst) { > > #if defined(__i386__) || defined(__amd64__) > > *dst = *src; > > #else > > bcopy(src, dst, ETHER_ADDR_LEN); > > #endif > > } > > Doesn't '*dst = *src' just work on all platforms? It does when you have an actual struct, but often in networking code you only have an array of bytes, and then casting the pointers from uint8_t * to full object pointers fails iff there is an alignment problem. Even on i386, it may be pessimal to use struct copying for 6 bytes, The bytes should be copied as 4+2 or 2+4 depending on alignment of the first bytes. Oops, not even that -- this reminds me of a problem with penalties for mismatched loads and stores which affects at least AthlonXP and Athlon64 significantly (10-20 cycle penalty = enough to copy 80-160 bytes unpenalized). The 6 should probably be copied as 2+2+2 or even as 1+1+1+1+1+1 to match previous stores and later loads, also as 2+2+2, etc. But if the 6 are part of another struct, they might be accessed as 8+0 or 4+4 as part of copying the full struct. gcc is not smart about this. Bruce _______________________________________________ [hidden email] mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-hackers To unsubscribe, send any mail to "[hidden email]" |
| Powered by Nabble | Edit this page |
